Subject: This is a tricky one
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Posted on: 2015-03-28 02:59:00 UTC

Number the barrels 1-1000 in Binary. Give each prisoner a number equivalent to one of the positions in the binary number. Each Barrel if it contained the poison would leave a different combination of prisoners dead as each Binary Number is unique. So ultimately they go and see which prisoners are dead. That would correspond to a 1 in the binary code. That would give what the binary code looks like and you can find the barrel that way.

And I do not know. Should you be concerned?

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